That depends on what you mean by a "20 ft semicircle".
A semi-circle is a half circle.
A 20 ft circle could be:
→ perimeter = 1/2π 20 ft + 20 ft
= 10π + 20 ft
≈ 51.42 ft
→ perimeter = 1/2 2π 20 ft + 2 x 20 ft
= 20π + 40 ft
≈ 102.08 ft
→ perimeter = 1/2 20 ft + 20 ft ÷ π
= 10 ft + 20/π ft
≈ 16.37 ft
However, if a 20 ft circle is a circle with a circumference (= perimeter) of 20 ft then a 20 ft semi-circle could be a semicircle with a perimeter of 20 ft
→ perimeter = 20 ft
The answer will depend on what measure of the semicircle is 5 inches: its radius or diameter.
dot know ..... just tell me the answer stupid computer
8*pi + 16 = 41.13 cm (approx)It depends on whether 8 cm is the radius or diameter of the semicircle.
5ft x 4 = 20ft
Perimeter l+l+w+w= 70ft Area LxW =300 sqft
Perimeter of a semicircle is the length of the half-circle plus the diameter. The whole circle would have a length of diameter times pi, but since it's only half... Perimeter of semicircle = (1/2*pi*D) + D
The circumference of a circle = 2π r = π a (where a is the base of the semicircle and is also the diameter of the circle) The perimeter of the semicircle = half the perimeter of the circle + the base length The perimeter of the semicircle = πa/2 + a = a(1 + π /2) feet
To find the perimeter of the curved section of the semi-circle: Perimeter of semicircle = Pi x radius If you also need to the find the perimeter of the straight part of the semicircle (the diameter), it is simply double the radius.
The perimeter of a semicircle with radius R is pi*R + 2*R = R*(pi + 2)
A semicircle is half a circle. So the perimeter of a semicircle is half the circumference of the whole circle plus the diameter, which is twice the radius: perimeter = 1/2 x 2{pi}r + 2r perimeter ~= 3.14x8 + 2x8 ~= 41.13cm
The answer will depend on what measure of the semicircle is 5 inches: its radius or diameter.
If the distance round the circle is 5.14 units then the distance round 1/2 of it would be 2.57 units.
20ft is the perimeter.
It is its diameter plus half of its circumference
The area would be 32*pi miles squared. The perimeter would be 16*pi miles.
Perimeter of the semicircle including its base: 180/360*pi*45+45 = 115.686 cm rounded to 3 decimal places
20ft