Want this question answered?
Its width works out as 15m and its length 20m and so 15*20 = 300 square m
Length = 20 mBreadth = 19 mPerimeter = 2(Length + Breadth) = 2(20 + 19) = 2 * 39 = 78 mArea = Length * Breadth = 20 * 19 = 380 m2
20m (4 sides x 5 = 20).
Perimeter = 20+20+4+4 = 48m
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m So that L = 44 - W Then area = L*W = 480 m2 is equivalents to (44 - W)*W = 480 Or W2 - 44W + 480 = 0 which gives W = 20 or W = 24 if W = 20 then L = 24 and if W = 24 the L = 20 However, since conventionally, L>W, L = 24m, W = 20m
Its width works out as 15m and its length 20m and so 15*20 = 300 square m
Perimeter of rectangle: 2*(20+15) = 70m
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
Assuming you're measuring a rectangle... Okay - you know the length of one side (10m), and the perimeter (36m) The two sides you know total 20m, therefore the sum of the other two sides MUST equal 16m divided by 2 = 8m.
The area of rectangle is : 20.0
A square with an area of 400m has a side length of 20m. The perimeter of a square of four times the length of one of its sides. Four times 20m is 80m. Therefore, the perimeter is 80m.
10 feet (3.05 meter) width & 22yards (20m) Length
Length = 20 mBreadth = 19 mPerimeter = 2(Length + Breadth) = 2(20 + 19) = 2 * 39 = 78 mArea = Length * Breadth = 20 * 19 = 380 m2
If the fence is parallel and extends 10m from each end of the length of the pool, add 20m to the length of the pool to find the length of the fence; find the width of the fence in the same manner. Hence, 50 + 20 = 70m (length of fence); 25 + 20 = 45m (width of fence). 2(L + W) = Perimeter, so 2 x 115m = 230m perimeter
20m (4 sides x 5 = 20).
Assuming that the measures given in the question refer to the lengths of the sides of the rectangle, the answer is 40 metres.
The answer is 20m