10+10+6+6 = 32
2 sides have length 10 and the other 2 sides have width 8 perimeter is sum of sides = 10+10+8+8 = 36
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
One presumes that you want the length of the sides.Our rectangle has sides x and x-5, The perimeter of a rectangle is just the sum of all four sides and in rectangles they come in pairs, so our equation is:50=2x + 2(x-5) expand to:50=2x +2x - 10 combine terms to:50=4x - 10 add +10 to both sides:10 + 50 = 4x - 10 +10 combine again60 = 4x divide both sides by 460/4 = 4x/4 simplify15 = x; therefore the sides are 15 and 10=15-5
2 sides have length 10 and the other 2 sides have width 8 perimeter is sum of sides = 10+10+8+8 = 36
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
A rectangle has two pairs of equal sides. So to calculate the perimeter, add two known sides and multiply by two. 45 + 10 = 55 55 x 2 = 110 Perimeter - 110 metres.
Perimeter of a rectangle 2L means two sides of length, thus multiply 2W means two sides of width; again multiply four sides around the rectangle and adding the L and W values gives the perimeter. Example: You have a rectangle that is 10 feet long and 6 feet wide. Find perimeter of rectangle that has 4 sides. Perimeter = 2(10 feet) + 2(6 feet) P = 20 feet + 12 feet Perimeter = 32 feet
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
I don't think you can guess that. If it was square it would be easy. But to find a perimeter its adding up all the sides. For it to be a rectangle you have to have 2 sets of sides that are equal to each other. So a possible answer could be 10
A rectangle with a perimeter of 36 units can have sides of any length as long as the lengths of the two differently-sized sides are equal to 18. For example, a rectangle with sides of 10 units and 8 units (don't forget to state what these units are, whether they are inches or centimetres or any other similar measurement), would have a perimeter of 36.
What is a rectangle were the area is 10 and the perimeter
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
No, you can not calculate an area if you know just the perimeter. For example, rectangle with sides of 10 and 20 would have a perimeter of 60 and an area of 200, but a square of sides 15 would have a perimeter of 60 and an area of 225. You need to know more details about the shape than just the perimeter.
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.