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Q: What is the perimeter of a rhombus with a side of 6 and an altitude of 5?

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Rhombus is an equilateral four sided form. If one side is 6, the perimeter is 4 x 6 = 24. The altitude makes no difference.

Base 1= 5 Perimeter 1=20 altitude 1= 4 A/P1 = 4*24/20 = 24/5 = 4.8 Base 2=3 Perimeter 2=12 altitude 2= 4*24/12 = 4*2 =8

The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.

The perimeter is 5 times the side length. A = 5s

5 x side

The perimeter is 26 units.

Perimeter = sum of all side lengths. For a square, s1 = s2 ... = s4, so Perimeter = 5+5+5+5 = 4(5) = 20cm

The perimeter of each pentagon is 25 inches.

4s=20

5-2

A rhombus has all four sides the same length.

Perimeter: 5+10+length of its 3rd side

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