The perimeter is 26 units.
You can make a perimeter with side lengths if 3, 3, 3, 3 or you could do a rectangle with side lengths of 4, 4, 2, 2. Finally you could do a rectangle with side lengths of 5, 5, 1, 1.
There are infininte combinations, such as 5+5+2.5+2.5.
Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224
28
One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).
You can make a perimeter with side lengths if 3, 3, 3, 3 or you could do a rectangle with side lengths of 4, 4, 2, 2. Finally you could do a rectangle with side lengths of 5, 5, 1, 1.
There are infininte combinations, such as 5+5+2.5+2.5.
It is 5 units * 20 units. A smaller perimeter can be attained by a square but the question specified a rectangle.
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224
28
One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).
Add up all 5 side lengths for the peremiter
Perimeter = sum of all side lengths. For a square, s1 = s2 ... = s4, so Perimeter = 5+5+5+5 = 4(5) = 20cm
You would not be able to find the perimeter of a pentagon without knowing the lengths of the sides. The perimeter is just all the side lengths added together, you should have 5 values to add.
A triangle has side lengths of 3, 4, and 5. The perimeter is 12 total. Perimeter is the total length of the outside of the object.
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.