The perimeter is 26 units.
You can make a perimeter with side lengths if 3, 3, 3, 3 or you could do a rectangle with side lengths of 4, 4, 2, 2. Finally you could do a rectangle with side lengths of 5, 5, 1, 1.
There are infininte combinations, such as 5+5+2.5+2.5.
Doubling the side lengths of a triangle results in a perimeter that is also doubled. The perimeter of a triangle is the sum of its three side lengths, so if each side length is multiplied by two, the total perimeter will similarly be multiplied by two. For example, if a triangle has side lengths of 3, 4, and 5, its original perimeter is 12, and if the side lengths are doubled to 6, 8, and 10, the new perimeter will be 24.
Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224
One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).
You can make a perimeter with side lengths if 3, 3, 3, 3 or you could do a rectangle with side lengths of 4, 4, 2, 2. Finally you could do a rectangle with side lengths of 5, 5, 1, 1.
There are infininte combinations, such as 5+5+2.5+2.5.
It is 5 units * 20 units. A smaller perimeter can be attained by a square but the question specified a rectangle.
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
Doubling the side lengths of a triangle results in a perimeter that is also doubled. The perimeter of a triangle is the sum of its three side lengths, so if each side length is multiplied by two, the total perimeter will similarly be multiplied by two. For example, if a triangle has side lengths of 3, 4, and 5, its original perimeter is 12, and if the side lengths are doubled to 6, 8, and 10, the new perimeter will be 24.
Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224
One possibility is 15 x 5 (therefore perimeter is 15 x 15 x 5 x 5 = 40cm).
28
Perimeter = sum of all side lengths. For a square, s1 = s2 ... = s4, so Perimeter = 5+5+5+5 = 4(5) = 20cm
Add up all 5 side lengths for the peremiter
You would not be able to find the perimeter of a pentagon without knowing the lengths of the sides. The perimeter is just all the side lengths added together, you should have 5 values to add.
A triangle has side lengths of 3, 4, and 5. The perimeter is 12 total. Perimeter is the total length of the outside of the object.