24 inches
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter is 24 inches. Each side is 6 inches. (8 times the length of one side) minus (24 inches) = 48 - 24 = 24 inches
The length is (18 centimeters) minus (the width)
For a regular four-sided figure, area divided by length or half the perimeter minus the length.
Perimeter minus two times the width will give you the two times the length. Area is found by multiplying the length by the width.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter is 24 inches. Each side is 6 inches. (8 times the length of one side) minus (24 inches) = 48 - 24 = 24 inches
The length is (18 centimeters) minus (the width)
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
Perimeter = Width x 2 + length x 2. To find width, you minus the length from perimeter because opposite of ADD is SUBTRACT.
For a regular four-sided figure, area divided by length or half the perimeter minus the length.
Perimeter minus two times the width will give you the two times the length. Area is found by multiplying the length by the width.
To be perfectly correct about it, a perimeter and an area can never be equal.A perimeter has linear units, while an area has square units.You probably mean that the perimeter and the area are the same number,regardless of the units.It's not possible to list all of the rectangles whose perimeter and area are thesame number, because there are an infinite number of such rectangles.-- Pick any number you want for the length of your rectangle.-- Then make the width equal to (double the length) divided by (the length minus 2).The number of linear units around the perimeter, and the number of square unitsin the area, are now the same number.
In geometry, Heron's (or Hero's) formula, named after Heron of Alexandria, states that the area A of a triangle whose sides have lengths a, b, and c is square root of semi perimeter multiply by semi perimeter minus a multiply by semi perimeter minus b multiply by semi perimeter minus c.
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
25a2 - 80a + 64
No. If you draw a rectangle there are four sides, the length of two of those sides are equal to the length, and the other two are equal to the width. Therefore: the perimeter, which is equal to all the sides added up, is equal to two times the length plus two times the width: or 2L+2W= Perimeter. If you know L and you know the perimeter you can solve it algebraically. the width equals the perimeter minus two times the length, all that divided by two, or W= (P-2L)/2 (when you do the algebra). you might be thinking about the area in which case if you knew the area and the length and you want to find the width you would divide the area by the length.