The perimeter of a rhombus is the sum of its 4 equal sides
Area equals base times height. The perimeter is 4 times the length of one side.
Perimeter of a rhombus = 4 x (length of one side)(Notice how closely the formula resemblesthe one for the perimeter of a square.)
Four times the side.
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
The area ( A ) of a rhombus can be calculated using the formula ( A = \frac{1}{2} \times d_1 \times d_2 ), where ( d_1 ) and ( d_2 ) are the lengths of the diagonals. The perimeter ( P ) of a rhombus is given by the formula ( P = 4s ), where ( s ) is the length of one side.
The perimeter of a rhombus-shaped highway sign with a 20-centimeter side is 80 centimeters.
60 units
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
Each side of the rhombus will have a length of 105/4 = 26.25 dm
Assuming 7.5 cm is the length of one side. Then the perimeter of a rhombus is 4 x 7.5 cm = 30 cm Like a square the four sides of a Rhombus are of equal length. It just that the angles are NOT right angles. . Its a 'lazy square'.
Rhombus is an equilateral four sided form. If one side is 6, the perimeter is 4 x 6 = 24. The altitude makes no difference.
Unless it is a rhombus (or square) you cannot.