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The lenth of second's pendulum of the earth is about 1 m What should be the length of second's pendulum on the moon?
Wiki User
∙ 10y ago
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
Wiki User
∙ 10y ago
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What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
How was a meter defined in 1791?
In the eighteenth century, there were two favoured approaches to the definition of the meter. One approach suggested that the metre be defined as the length of a 'seconds pendulum' (pendulum with a half-period of one second). Another suggestion was defining the metre as one ten-millionth of the length of the Earth's meridian along a quadrant (the distance from the Equator to the North Pole).In 1791, the French Academy of Sciences selected the latter definition (the one related to Earth's meridian) over the former (the one with the pendulum) because the force of gravity varies slightly over the surface of the Earth's surface, which affects the period of a pendulum.
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
If the period of a pendulum on Earth is 1.8 seconds what is the length of the pendulum?
Approx 80.5 centimetres.
What is the period of a simple pendulum 45 cm long on the Earth?
The period of a simple pendulum can be calculated using the formula T = 2π * sqrt(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. On Earth, the value of g is approximately 9.81 m/s^2. Converting the length of the pendulum to meters (0.45 m), the period would be about 1.42 seconds.
What is the period on earth of a pendulum with a length of 1.0 meter?
The period of a pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum (1.0 meter in this case), and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, the period of a pendulum with a length of 1.0 meter on Earth is approximately 2.006 seconds.
A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2π√(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
What is the period of a pendulum on Neptune compared to earth?
equation for time in pendulum: t = 2 * pi * ( sq. root (l / g)) key: t = time elapsed ( total, back and forth ) l = length , from pivot to centre of gravity g = acceleration due to gravity say 1 metre length pendulum on earth @ 9.82 (m/s)/s, t = 2.005 seconds same pendulum on neptune @ 11.23 (m/s)/s, t = 1.875 seconds
If a simple pendulum with a period of 1 second is set in motion of the moon what is the new period of this pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
What is the effect of changing length or mass of the pendulum on the value of g?
Changing the length or mass of a pendulum does not affect the value of acceleration due to gravity (g). The period of a pendulum depends on the length of the pendulum and not on its mass. The formula for the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
How was a meter defined in 1791?
In the eighteenth century, there were two favoured approaches to the definition of the meter. One approach suggested that the metre be defined as the length of a 'seconds pendulum' (pendulum with a half-period of one second). Another suggestion was defining the metre as one ten-millionth of the length of the Earth's meridian along a quadrant (the distance from the Equator to the North Pole).In 1791, the French Academy of Sciences selected the latter definition (the one related to Earth's meridian) over the former (the one with the pendulum) because the force of gravity varies slightly over the surface of the Earth's surface, which affects the period of a pendulum.
