1/4 Hertz or 1.4 per second.
0.1 seconds
It doesn't matter what unit you use to measure the physical length of the pendulum. As a matter of fact, it doesn't matter what unit you use to measure the duration of its period either. If both are at rest on the same planet, then the penduum with the longer string has the longer period. Period!
Oh, what a lovely question! To find the frequency of a wave when you know the period, you simply take the reciprocal of the period. So, if the period is 40 seconds, the frequency would be 1 divided by 40, which equals 0.025 Hz. Isn't that just a happy little calculation?
The frequency of a wave can be calculated using the formula f = 1/T, where f represents frequency and T represents period. In this case, with a period of 6 seconds, the frequency would be f = 1/6 = 0.1667 Hz. This means that the wave completes 0.1667 cycles in one second.
Making the length of the pendulum longer. Also, reducing gravitation (that is, using the pendulum on a low-gravity world would also increase the period).
The period of a simple pendulum is the time it takes for one full oscillation (swing) back and forth. To find the period, you can use the formula: Period = 1 / Frequency. So, if the frequency is 20 Hz, the period would be 1/20 = 0.05 seconds.
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
For a simple pendulum: Period = 6.3437 (rounded) seconds
The period of the pendulum is the time taken for one complete back-and-forth motion. In this case, since the pendulum takes 3 seconds to move away and 3 seconds to come back, the total time for one full cycle is 6 seconds. Therefore, the period of the pendulum is 6 seconds.
The frequency of the pendulum is 1/3 Hz, as frequency is the number of complete cycles (swings) per second. Since it completes one cycle every 3 seconds, the frequency is the reciprocal of the time period, which is 1/3 Hz.
mhz ( megahertz) is a unit of frequency while seconds is a unit of time ,so normally they can't be converted to one another.But if you want to convert mhz to seconds (as in case of pendulum to find out the time period of the pendulum if frequency is provided) multiply the frequency by 106 (to convert mega hertz int hertz) and then take out the reciprocal of the quantity(as frequency=1/time period)
Frequency = (1)/(period) .If the period is still 4 seconds, then the frequency = (1)/(4 seconds) = 0.25 per second = 0.25 Hz.
The period is the reciprocal of frequency, so for a frequency of 440 Hz, the period would be 1/440 seconds, which is approximately 0.00227 seconds.
since the period is the reciprocal of frequency, the period is 1/10 seconds.
Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)
Time period = 1 / frequency. Frequency = 1 / time period. Period T = 1 / 1.2 = 0.8333333 seconds.
The frequency of a tone with a period of 100 milliseconds is 10 Hz. Frequency is the reciprocal of period, so to find frequency, you would take 1 divided by the period in seconds (0.1 seconds in this case).