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What is the perpendicular bisector equation of the line segment whose end points are at 3 5 and 7 7?
Wiki User
∙ 7y ago
End points: (3, 5) and (7, 7)
Midpoint: (5, 6)
Slope: 1/2
Perpendicular slope: -2
Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
Wiki User
∙ 7y ago
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Are any points on the perpendicular bisector of a segment equally distant from the 2 endpoints?
All of the points on a perpendicular bisector are equidistant from the endpoints of the segment.
What is the perpendicular bisector equation of the line segment with endpoints of -7 -3 and -1 -4?
End points: (-7, -3) and (-1, -4) Midpoint: (-4, -3.5) Slope: -1/6 Perpendicular slope: 6 Perpendicular bisector equation: y--3.5 = 6(x--4) => y = 6x+20.5
What is the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
What is the perpendicular bisector equation that meets the line segment of 7 3 and -6 1 showing work in addition to the answer?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular bisector equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5
is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?
true
Are any points on the perpendicular bisector of a segment equally distant from the 2 endpoints?
All of the points on a perpendicular bisector are equidistant from the endpoints of the segment.
What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
What is the difference between a perpendicular line and a perpendicular bisector?
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
What is the perpendicular bisector equation of the line segment whose end points are at -2 4 and -4 8 on the Cartesian plane?
End points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 Perpendicular bisector equation: y -6 = 1/2(x--3) => y = 0.5x+7.5
How do you prove that the points of 3 -4 and 6 5 lie on the bisector equation that is perpendicular to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -80 Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13 Proof: (3, -4) and (6, 5) satisfies the above equation.
What is the perpendicular bisector equation of the line segment with endpoints of -7 -3 and -1 -4?
End points: (-7, -3) and (-1, -4) Midpoint: (-4, -3.5) Slope: -1/6 Perpendicular slope: 6 Perpendicular bisector equation: y--3.5 = 6(x--4) => y = 6x+20.5
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the perpendicular bisector equation of the line segment joined by the points -2 4 and -4 8?
Points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 or 0.5 Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5
What is the perpendicular bisector equation that meets the line segment of -2 2 and 6 4 at its midpoint showing work?
Points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular bisector equation: y-3 = -4(x-2) => y = -4x+11
What is the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?
true
What is the perpendicular bisector equation that meets the line segment of 7 3 and -6 1 showing work in addition to the answer?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular bisector equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5
