Midpoint = (3+7)/2, (5+7)/2 = (5, 6)
Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2
Slope of the perpendicular = -2
Equation of the perpendicular bisector: y-y1 = m(x-x1)
y-6 =-2(x-5)
y = -2x+10+6
Equation of the perpendicular bisector is: y = -2x+16
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
it depends on how long or how many joining segments it has. normally one line segment contains only one midpoint. Unless it has a joining segment there is only one midpoint.
I'm assuming the points are (-76, -3) and (7, -63). If that's the case then the equation can be found by the following. (1) First find the slope of a line between these two point, m: m = (y1 - y2)/(x1 - x2) = (-3 - -63) / (-76 - 7) = - 60/83 (2) The equation for a line is y = mx + b, since we have the slope m already, use one of the points listed to solve for the intercept b. (I used the first one: -76, -3) -3 = -60/83*(-76) + b -3 = 4560/83 + b b = -4809/83 So the equation of the line joining these two point is: Y = (-60/83)X - (4809/83)
midsegment
A line joining any vertex to the midpoint of the opposite side. Because of the properties of an equilateral triangle, this line may be described as the median, the perpendicular bisector of a side or an angle bisector.
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
1 Points: (1, 2) and (3, 4) 2 Slope: (2-4)/(1-3) = 1 3 Perpendicular slope: -1 4 Midpoint: (1+3)/2 and (2+4)/2 = (2, 3) 5 Equation: y-2 = 1(x-1) => y = x+1 6 Bisector equation: y-3 = -1(x-2) => y = -x+5
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
First find the midpoint of (-2, 5) and (-8, -3) which is (-5, 1) Then find the slope of (-2, 5) and (-8, -3) which is 4/3 Slope of the perpendicular bisector is the negative reciprocal of 4/3 which is -3/4 Now form an equation of the straight line with a slope of -3/4 passing through the point (-5, 1) using the formula y-y1 = m(x-x1) The equation works out as: 3x+4y+11 = 0
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
Their values work out as: a = -2 and b = 4
The perpendicular bisector of the straight line joining the two points.