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If you mean the perpendicular distance then it is worked out as follows:-

Equation: y = 2x+10

Perpendicular slope: -1/2

Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10

The two equations intersect at: (-2,6)

Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.

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Q: What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?
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