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The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5

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Q: What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?
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What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?

If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.


How would you find the perpendicular distance from the point 7 5 to the line 3x plus 4y -16 equals 0 on the Cartesian plane?

Equation of line: 3x+4y-16 = 0 or y = -3/4x+4 Slope of line: -3/4 Slope of perpendicular line: 4/3 Perpendicular equation: y-5 = 4/3(x-7) or 3y = 4x-13 Both equations intersect at: (4, 1) Perpendicular distance from (7, 5) to (4, 1) = 5 units using distance formula


Find the slope of the line perpendicular to the line y equals 2x plus 1?

The slope of the perpendicular is -(1/2) .


What is the directrix of a parabola?

"From the geometric point of view, the given point is the focus of the parabola and the given line is its directrix. It can be shown that the line of symmetry of the parabola is the line perpendicular to the directrix through the focus. The vertex of the parabola is the point of the parabola that is closest to both the focus and directrix."-http://www.personal.kent.edu/~rmuhamma/Algorithms/MyAlgorithms/parabola.htm"A line perpendicular to the axis of symmetry used in the definition of a parabola. A parabola is defined as follows: For a given point, called the focus, and a given line not through the focus, called the directrix, a parabola is the locus, or set of points, such that the distance to the focus equals the distance to the directrix."-http://www.mathwords.com/d/directrix_parabola.htm


What is the slope of a line that is perpendicular to the graph of 8x plus y equals 6?

+ 1/8

Related questions

What is the perpendicular distance from the point 2 4 to the straight line equation of y equals 2x plus 10 on the Cartesian plane?

It works out as: 2 times the square root of 5


What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?

Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5


What is always perpendicular to -3x plus y equals 2?

The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin


What is the perpendicular distance from the point 3 -4 on the Cartesian plane to the line 5x -2y equals 3 rounding off work to three decimal places?

Equation: 5x-2y = 3 Perpendicular equation: 2x+5y = -14 Both equations intersect at: (-13/29, -76/29) Perpendicular distance to 3 decimal places: 3.714


What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?

Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula


What is the perpendicular distance from the point 19 29 that meets the straight line equation 3y equals 9x plus 18 on the Cartesian plane showing work and answer to an appropriate degree of accuracy?

If: 3y = 9x+18 then y = 3x+6 with a slope of 3 Perpendicular slope: -1/3 Perpendicular equation: y-29 = -1/3(x-19) => 3y = -x+106 Both equations intercept at: (8.8, 32.4) Perpendicular distance: square root of (8.8-19)^2+(32.4-29)^2 = 10.75 rounded


What is the perpendicular distance from the point of 2 4 on the Cartesian plane to the straight line equation of y equals 2x plus 10 showing key stages of work?

1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5


What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?

If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.


What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement


What is the perpendicular from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane with work shown?

If you mean the perpendicular distance then it is worked out as follows:- Equation: y = 2x+10 Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 The two equations intersect at: (-2,6) Perpendicular distance is the square root of: (-2-2)2+(6-4)2 = 4.472 to 3 d.p.


What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?

Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula


How can the parabolic form y equals ax2 be plotted as a straight line on cartesian graph paper?

It cannot.