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Phase shift of y equals sin x-2?
Shift = +2
If you are given the equation of an normal sine curve how would you determine its period?
a normal sine curve exists with the formula Asin(Bx+C)+D. The formula to derive a phase shift would be such: 2pi/B (for whatever value B exists at). Thus, for a normal sine curve (sin(x) we would get 2pi/1, and arrive at 2pi for the period.
What is the formula for calculating time displacement in phasors of the form Asin b plus c?
The graph of y = A sin (Bx + C) is obtained by horizontally shifting the graph of y = A sin Bx, where 1) Amplitude = |A|, the maximum of y is A, if A > 0 and -(-A) if A < 0 The minimum of y is -A if A > 0 and A if A < 0 2) Period = (2pi)/B 3)Phase shift = C/B So that the starting point of the cycle is shifted from x = 0 to x = C/B. If C/B > 0 the shift is to the right. If C/B < 0 the shift is to the left.
Determine the period of y equals -3 sin x?
the period is 2pi. period is 2pi/b and the formula is y=AsinBx.
How do you solve sin2x plus sinX equals 0?
Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,
Phase shift of y equals sin x-2?
Shift = +2
If you are given the equation of an normal sine curve how would you determine its period?
a normal sine curve exists with the formula Asin(Bx+C)+D. The formula to derive a phase shift would be such: 2pi/B (for whatever value B exists at). Thus, for a normal sine curve (sin(x) we would get 2pi/1, and arrive at 2pi for the period.
What is sin of 3 pi over 2?
Sin(3pi/2) = Sin(2pi - pi/2) Double angle Trig. Identity. Hence Sin(2pi)Cos(pi/2) - Cos(2pi) Sin(pi/2) Sin(2pi) = 0 Cos(pi/2) = 0 Cos(2pi) = 1 Sin(pi/2) = 1 Substituting 0 x 0 - 1 x 1 = 0 - 1 = -1 The answer!!!!!
What is the formula for calculating time displacement in phasors of the form Asin b plus c?
The graph of y = A sin (Bx + C) is obtained by horizontally shifting the graph of y = A sin Bx, where 1) Amplitude = |A|, the maximum of y is A, if A > 0 and -(-A) if A < 0 The minimum of y is -A if A > 0 and A if A < 0 2) Period = (2pi)/B 3)Phase shift = C/B So that the starting point of the cycle is shifted from x = 0 to x = C/B. If C/B > 0 the shift is to the right. If C/B < 0 the shift is to the left.
What is the phase shift for a sin wave with the maximum amplitude at time zero?
For a sine wave with maximum amplitude at time zero, there is no phase shift. The wave starts at its peak at time zero, and therefore, its phase angle is zero.
Determine the period of y equals -3 sin x?
the period is 2pi. period is 2pi/b and the formula is y=AsinBx.
How do you solve sin2x plus sinX equals 0?
Sin(2x) + Sin(x) = 0 2Sin(x)Cos(x) + Sin(x) = 0 Factor 'Sin*(x)' Sin(x) (2Cos(x) + 1 = 0 Hence Sin(x) = 0 x = 0 , 180(pi) , 360(2pi) et.seq., & 2Cos(x) = -1 Cos(x) = -1/2 = -0.5 x = 120, 150, 480, et.seq.,
How do you find theta if 2sin theta plus 1 equals 0 and 0 is less than or equal to theta which is less than 2pi?
2 sin(x) + 1 = 0 2 sin(x) = -1 sin(x) = -1/2 x = 210° and 330°
What equation is this x equals a sin wt?
sine wave, with a period of 2pi/w
What is the equation of a sine wave?
The equation of a sine wave is y A sin(Bx C) D, where A represents the amplitude, B is the frequency, C is the phase shift, and D is the vertical shift.
What s the amplitude and period of y cos 8x?
y = A sin Bx y = A Cos BxAmplitude = APeriod = 2pi/Bso....Amplitude = 1Period = 2pi/8
What is the difference between phase and frequency?
No matter what frequency, there are 360 degrees that can be associated with it (the phase). Here's an equation to summarize: V(t) = A sin ([w*t] + p) A is amplitude w = frequency p = phase shift
