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Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
it depends on the number, but if that number was represented by x, then it would be x:100 or x/100. a ratio is the same as division.
number of boys = ratio of boys x total strength / total ratio = 5 x 27/9 = 5 x 3 = 15 number of girls = ratio of girls x total strength / total ratio = 4 x 27/9 = 4 x 3 = 12 verification: 15 + 12 = 27
x = 740.
for x that makes the first ratio equivalent to the second ratio of x to 14 , 56 to 98
3:1
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The phenotypic ratio will be 1:3.his son will be color blind.
3:1
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
These are the phenotypic ratios of each outcome: Dominant A and B: 9/16 Dominant A and recessive B: 3/16 Recessive A and dominant B: 3/16 Recessive A and B: 1/16
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
Two quantities are in a Golden Ratio if the ratio of the bigger quantity to the smaller quantity is the same as the ratio of the sum of the two quantities to the bigger quantity. In algebraic form, if the two quantities are x and y, and x is the bigger of the two, then they are in the Golden Ratio if x/y = (x+y)/x and that ratio is the Golden Ratio. which equals (1 + √5)/2.
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
In accordance to Medelian's first law,you will receive a F1 (Generation 1) of all the dominant traits (If you G is Green,it will be all green and if you G is yellow,it will be all yellow).It is only when during F2 (Generation 2) as you interbreed them (F1 x F1) will you receive a Phenotypic ratio of 3:1.In this,if your G is green,it will be of a ratio of 3 greens to 1 yellow pea pods. Basically Gg x Gg will give rise to 2 phenotypic classes of progeny,G and g,in a ratio of 3:1 provided that G is Dominant to g.