12.5
Assuming 4x = 5y Then x/y = 5/4
equals x+2 PROVIDED x is not -2. If x is -2, the ratio is not defined.
What is the ratio of two odd functions? Ans: f, g are odd func on the same domain D. Let r = f / g, assuming g non zero everywhere on D. r(-x) = f(-x) / g(-x) = -f(x) / [-g)(x)] = f(x) / g(x) = r(x), and so r is an even function.
To convert ratio to percentage use the following method for a ratio where a:b means the same as a/b, then percentage = ( a / ( 1 - a ) ) x 100 so for a/b = 0.37 then percentage = (0.37 / (1 + 0.37)) x 100 = 27% a/b = 0.5, % = 0.33 a/b = 1, % = 0.5
When crossing RrGg with rrGg, the resulting genotypic ratio is 1 RRGG: 2 RrGg: 1 rrgg. Therefore, 25% of the offspring will be wrinkled yellow.
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
12.5
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
A monohybrid ratio refers to the genotypic and phenotypic ratio seen in the offspring of a genetic cross involving only one trait. For example, in a monohybrid cross between two heterozygous individuals (Aa x Aa), the genotypic ratio among the offspring would be 1:2:1 for AA:Aa:aa, and the phenotypic ratio would be 3:1 for the dominant trait to the recessive trait.
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
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The phenotypic ratio of the cross AaBb x AaBb is 9:3:3:1, which represents the different possible combinations of genotypes for the offspring based on the principles of Mendelian genetics. This ratio indicates that 9 out of 16 offspring will exhibit the dominant phenotype for both traits, while 3 out of 16 will exhibit one dominant and one recessive phenotype, 3 out of 16 will exhibit the other dominant and recessive phenotype, and 1 out of 16 will exhibit both recessive phenotypes.
You would expect a 1:1 ratio of offspring with a long body (LL) to offspring with a short body (ll) due to the incomplete dominance of the gene for body length in Drosophila.