3:1
12.5
Assuming 4x = 5y Then x/y = 5/4
equals x+2 PROVIDED x is not -2. If x is -2, the ratio is not defined.
What is the ratio of two odd functions? Ans: f, g are odd func on the same domain D. Let r = f / g, assuming g non zero everywhere on D. r(-x) = f(-x) / g(-x) = -f(x) / [-g)(x)] = f(x) / g(x) = r(x), and so r is an even function.
To convert ratio to percentage use the following method for a ratio where a:b means the same as a/b, then percentage = ( a / ( 1 - a ) ) x 100 so for a/b = 0.37 then percentage = (0.37 / (1 + 0.37)) x 100 = 27% a/b = 0.5, % = 0.33 a/b = 1, % = 0.5
Not enough info has been provided here. You would have to indicate what R and G represent, and what the various phenotypic outcomes could be, in order to determine the percentages.
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
12.5
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
A monohybrid ratio refers to the genotypic and phenotypic ratio seen in the offspring of a genetic cross involving only one trait. For example, in a monohybrid cross between two heterozygous individuals (Aa x Aa), the genotypic ratio among the offspring would be 1:2:1 for AA:Aa:aa, and the phenotypic ratio would be 3:1 for the dominant trait to the recessive trait.
To determine the phenotypic ratio of the cross PpRr (heterozygous for both traits) and Pprr (heterozygous for the first trait and homozygous recessive for the second), we can set up a Punnett square. The offspring will display four phenotypes based on dominant and recessive traits for both characteristics. The resulting ratio is 3:1 for the first trait (P vs. p) and 1:1 for the second trait (R vs. r), leading to a combined phenotypic ratio of 3:1:1:1 (3 dominant for the first trait and 1 recessive for both traits).
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
Suck dickkk bitchh
The phenotypic ratio of the cross AaBb x AaBb is 9:3:3:1, which represents the different possible combinations of genotypes for the offspring based on the principles of Mendelian genetics. This ratio indicates that 9 out of 16 offspring will exhibit the dominant phenotype for both traits, while 3 out of 16 will exhibit one dominant and one recessive phenotype, 3 out of 16 will exhibit the other dominant and recessive phenotype, and 1 out of 16 will exhibit both recessive phenotypes.