3:1
12.5
Assuming 4x = 5y Then x/y = 5/4
equals x+2 PROVIDED x is not -2. If x is -2, the ratio is not defined.
What is the ratio of two odd functions? Ans: f, g are odd func on the same domain D. Let r = f / g, assuming g non zero everywhere on D. r(-x) = f(-x) / g(-x) = -f(x) / [-g)(x)] = f(x) / g(x) = r(x), and so r is an even function.
Let x be one integer and x+4 will be the other. Therefore, X/(X+4) = 7/9 since the ratio of the two numbers is 7/9 (or less than 1) the larger number will be on the bottom. If you cross multiply the ratios, you can solve for x. X*9 = (X+4)*7 9X = 7X + 28 2X = 28, so X = 14 and the other number is 18. The ratio of 14 to 18 is 7/9.
Not enough info has been provided here. You would have to indicate what R and G represent, and what the various phenotypic outcomes could be, in order to determine the percentages.
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
12.5
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
A monohybrid ratio refers to the genotypic and phenotypic ratio seen in the offspring of a genetic cross involving only one trait. For example, in a monohybrid cross between two heterozygous individuals (Aa x Aa), the genotypic ratio among the offspring would be 1:2:1 for AA:Aa:aa, and the phenotypic ratio would be 3:1 for the dominant trait to the recessive trait.
When you cross two hybrids, the ratio of the offspring typically depends on the genetic makeup of the hybrids and the traits being studied. For example, if both hybrids are heterozygous for a single trait (e.g., Aa x Aa), the expected phenotypic ratio in the offspring would be 3:1 for dominant to recessive traits. If the hybrids are heterozygous for two traits (e.g., AaBb x AaBb), the phenotypic ratio would be 9:3:3:1. Always consider the specific genetics involved for accurate predictions.
To determine the phenotypic ratio of the cross PpRr (heterozygous for both traits) and Pprr (heterozygous for the first trait and homozygous recessive for the second), we can set up a Punnett square. The offspring will display four phenotypes based on dominant and recessive traits for both characteristics. The resulting ratio is 3:1 for the first trait (P vs. p) and 1:1 for the second trait (R vs. r), leading to a combined phenotypic ratio of 3:1:1:1 (3 dominant for the first trait and 1 recessive for both traits).
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
When a true-breeding tall plant (TT) is crossed with a true-breeding short plant (tt), all the offspring in the first generation (F1) will be heterozygous (Tt) and exhibit the tall phenotype, as tall (T) is dominant over short (t). Therefore, the phenotypic ratio of the offspring will be 100% tall. If these F1 plants are then crossed with each other (Tt x Tt), the resulting phenotypic ratio in the second generation (F2) will be 3 tall (TT or Tt) to 1 short (tt).