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in case of derivative w.r.t time

first derivative with a variable x gives velocity

second derivative gives acceleration

thid derivative gives jerk

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Q: What is the physical application of third- and fourth-order derivatives with respect to distance e g first derivative is slope?
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Relate distance velocity acceleration using derivatives with respect to time?

I'm not sure about the respect to time, but the equation for velocity is the first derivative of the equation of time (w/ respect to distance) and acceleration is the second derivative. I'm sorry, I don't think I properly answered your question, but this information should be correct. . :)


What is the purpose of the 2rd and third derivatives in Calculus?

1st derivative is the rate of change. If, for example, you start driving your car from home, and x is a measure of distance from your home , then d/dx is your speed. In that same example, the 2nd derivative would be your acceleration (change of speed). And the 3rd derivative would be your change in acceleration (also known as 'jerk').


What is the scientific definition for speed?

First derivative of distance with respect to time.


How do you fing the speed in Algebra?

Average Speed = Total Distance/Total Time.Instantaneous Speed = Derivative of Distance with respect to Time.


The slope of the distance-time graph gives the?

Time derivative of displacement which is... speed!


What is the formula for solving acceleration?

acceleration = twice the distance over time, or the derivative of velocity with respect to time


What is the rate of change of velocity with distance?

acceleration/decceleration it is the second derivative of a displacement vs time function


How do you find the acceleration and initial velocity given only the distance and time?

If you are only given total distance and total time you cannot. If you are given distance as a function of time, then the first derivative of distance with respect to time, ds/dt, gives the velocity. Evaluate this function at t = 0 for initial velocity. The second derivative, d2s/dt2 gives the acceleration as a function of time.


What is the application of a force over some distance?

Work.


What is acceleration of a particle if position of a particle at any instant of time t is given by x equals t 3?

velocity is 1st derivative of distance with respect to time acceleration is 2nd derivative of distance with respect to time dx/dt = velocity = 3t^2 dv/dt = acceleration = 6t


What is a speed?

Basically "speed" tells you how fast something moves. It is defined as a distance divided by a time (more precisely, in the case of variable speed, the derivative of distance with respect to time).


Is defined as force acting over a distance?

In elementary physics the the application of force over a distance can regard gravitation. Furthermore, the application of force over an area regards the measure of pressure.