The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100
Subtracting x² +100 from both sides you get 20x = -20x
that will only be true when x = 0.
At x = 0, y = 100 for both equations - so the point of contact would be
(0,100)
There is no connection between the given curves because when they are combined into a single quadratic equation the discriminant of the equation is less than zero which means they share no valid roots.
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
3 squared equals 9. 4 squared equals 16. So the square root of 10 must be between 3 and 4.
It is (-0.3, 0.1)
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
4
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
C equals the square root of 1000 or 31.622776601683793319988935444327...