Since the line "y = x - 8" is already solved for "y", you can replace "y" for "x - 8" in the equation for the curve, then solve the single equation. Usually this requires using the quadratic equation (or equivalent methods, such as factoring) at some point.
Another Answer:-
If: 4x² + 13x + 1 = y and y = x - 8
Then: 4x² + 13x + 1 = x - 8
Deduct x and add 8 to both sides and so: 4x² + 12x + 9 = 0
Solving the above quadratic equation by factorization:
4x² + 12x + 9 = 0 → (2x + 3)² = 0
→ 2x + 3 = 0
→ x = -3/2
→ y = -3/2 - 8 = -19/2
Therefore point of contact by substitution: (-3/2, -19/2)
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)
If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)
-2
-2
It is (-0.3, 0.1)
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
0
4