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Line equation: x-2y +12 = 0

Circle equation: x^2 +y^2 -x -31 = 0

Combine both equations together to form: 5y^2 -50y +125 = 0

Divide all terms by 5: y^5 -10y +25 = 0

Factorizing: (y-5)(y-5) = 0 => y = 5

Point of contact by substitution is at: (-2, 5)

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Q: What is the point of contact when the line x -2y plus 12 equals 0 touches the circle x squared plus y squared -x -31 equals 0?
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