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What is the point of intersection between points 2x-4 and x plus 1?
Wiki User
∙ 13y ago
x,y = 5,6 or x = 5 and y = 6
Wiki User
∙ 13y ago
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What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
How many points of intersection are the between x2 and x2 plus 5?
There are none. Those two curves do not intersect.
What is the point of intersection if y equals x plus 1 and x equals -x plus 1x?
2
What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
What are the points of intersection between the equations of 2x plus y equals 5 and x2 -y2 equals 3?
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
How many points of intersection are the between x2 and x2 plus 5?
There are none. Those two curves do not intersect.
What is the point of intersection if y equals x plus 1 and x equals -x plus 1x?
2
What is the intersection point of the lines 2x plus y equals 2 and -3x-2y equals -6?
The intersection is (-2, 6)
What is the point of intersection of the lines 6y equals -x -25 and 6x plus 20.5 -y equals 0?
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
What are the points of intersection between the equations of 2x plus y equals 5 and x2 -y2 equals 3?
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
What is point 9 plus point 3?
points 12
What is the point of intersection between the lines y equals 4x -1 and 3y -8x plus 2 equals 0?
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
Where are the points of intersection with the x and y axes when y equals 8x2 -26x plus 15 is plotted on the Catesian plane?
Equation: y = 8x^2 -26x+15 Equation when factorized: y = (4x-3)(2x-5) When x = 0 then y = (0, 15) which is the point of intersection on the y axis When y = 0 then x = (3/4, 0) and (5/2, 0) which are the points of intersection on the x axis
How would you draw a graph that passes through the point -4 -2 and has a gradient of 2 and the point of intersection for this line and for the line y equals x plus 2?
You have to draw the x and y axes, probably from -5 to 5 on each Then plot the point (-4,-2) and the point (0,2) because the intercept is two. Then draw a line between the two points, and continue it either side!
