Wiki User
∙ 6y agoEquation: y = 8x^2 -26x+15
Equation when factorized: y = (4x-3)(2x-5)
When x = 0 then y = (0, 15) which is the point of intersection on the y axis
When y = 0 then x = (3/4, 0) and (5/2, 0) which are the points of intersection on the x axis
Wiki User
∙ 6y agoThe points of intersection are: (7/3, 1/3) and (3, 1)
Points of intersection work out as: (3, 4) and (-1, -2)
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
Any metric or non-metric units can be represented by points on the plotted line.
They work out as: (-3, 1) and (2, -14)
The points of intersection are: (7/3, 1/3) and (3, 1)
Points of intersection work out as: (3, 4) and (-1, -2)
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
Any metric or non-metric units can be represented by points on the plotted line.
They work out as: (-3, 1) and (2, -14)
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
Radiation is suitable for locating the objects from a single point , while Intersection is suitable for the inaccessible points by intersection of rays drawn from two instrument stations.
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
If it is plotted correctly, there is no reason for it to be anything but accurate.
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)