You can work this out by solving one of the equations for either of the variables, and substituting that solution for that variable in the other equation. That will give you one either the X or Y co-ordinate for the point of intersection, and you can calculate the other one with one by plugging that back into one of the original equations:
y = x + 4
y = 3x
∴ 3x = x + 4
∴ 2x = 4
∴ x = 2
y = 3x
∴ y = 6
So the point of intersection between the lines y = 3x and y = x + 4 is (2, 6).
The intersection is (-2, 6)
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
2
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
The coordinates of the point of intersection is (1,1).
When x = -2 then y = 4 which is the common point of intersection of the two equations.
(4, -7)
It works out that they intersect at: (4, -7)
They intersect at the point of: (-3/2, 11/4)
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
Yes its on the line.
By a process of elimination and substitution the lines intersect at: (4, -7)