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What is the pressure of a can with a volume of 250 mL containing 2.3 g of C3H8 if the can is at 298 K?
Wiki User
∙ 12y ago
You must use the equation PV = nRT, where
P = pressure in ATM
V = volumes in L
n = moles of gas
R = gas constant (.0821 mol*ATM/L*K)
T = Temperature in K
2.3g C3H8 / 44.09 g (molecular weight) = 0.052 moles
250mL = 0.25 L
P(0.25 L) = (0.052 moles)(0.0821 mol*ATM/L*K)(298K)
P = 5.09 ATM
Wiki User
∙ 12y ago
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Under a pressure of 200 kPa a confined gas has a volume of 2500 cubic meters The pressure acting on the gas is increased to 500 kPa What is the new volume of the gas if the temperature remains t?
p1.V1 / T1 = constant = p2.V2 / T2 (the 'Boyle&Gay-Lussac' Law)250*15/100 = 500*30/ T2T2 = 400K
Which refrigerants are high pressure?
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What is the cross section of a cuboid if the volume is 250 cubic centimeters?
If you mean what is the right cross sectional area of a cube with a volume of 250 cubic centimeters the answer is 40 cc (really 39.685)
What volume would be needed to dilute a 5.7 M solution to a final concentration of 0.35 M and a volume of 250 mL?
By using the formula V1 x N1 = V2 x N2 Taking V1= 250 ml; N1= 0.35M; N2= 5.7M. V2 = volume of 5.7M needed to dilute V2 = V1 x N1 N2 = 250 x 0.35 = 15.35ml 5.7
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Millimeters can't be converted to liters. Millimeters measure length, while liters measure volume.
Volume of 250 ml at a pressure of 7.50 atmospheres how much volume would this be at a room pressure of one atmosphere in ml?
1875 mL
The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?
400 mL (Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer
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