34
2,17
2 x 17 = 34
23 is already prime.
231 77,3 11,7,3 3 x 7 x 11 = 231
36 18,2 9,2,2 3,3,2,2 2 x 2 x 3 x 3 = 36
456
all the numbers are prime numbers therefore the prime factorization of 2*2*5*11=2*2*5*11
13 is already prime. Just write it down.
18 9,2 3,3,2
60 30,2 15,2,2 5,3,2,2
As a product of its prime factors: 2*2*2*5*19 = 760
Divide by 3 or 5. 3 x 5 = 15
Yes, 2x2x2x5 can be written in prime factorization as 2^3 x 5. In prime factorization, we break down a number into its prime factors. Here, 2 is a prime number and appears three times, so we write it as 2^3. The number 5 is also a prime number and appears once, so we simply write 5.
It is: 2*2*5*7 = 140 by dividing it by each prime number that has no remainder