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Q: What is the prime factorization of 230 written with exponents?

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As a product of its prime factors: 2*5*23 = 230

The prime factorization of 230 is:2 X 5 X 232 x 5 x 23

2 x 5 x 23 = 230

2*5*23.

2 x 5 x 23 = 230

230 = 2 x 5 x 23

230 115,2 23,5,2 2 x 5 x 23 = 230

230

230

230 / 2 = 115 115 / 5 = 23 so the prime fact. is 2 x 5 x 23

divide 230 by lowest prime possible (2) gives 115, divide 115 by lowest prime possible (5) gives 23, 23 is itself a prime so prime factors of 230 are 2, 5, and 23

2^1*5^1*23^1= 230 We can divide 230 to 2, 3, and 23. We cannot divide more from this because they are already all prime numbers!

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