The lowest prime number that will divide evenly into 39 is 3, so 3 is a prime factor of 39. 39/3 = 13, and 13 is a prime number that is also a factor of 39. The prime factorization of 39 is 3 x 13.
The GCF of 27 and 39 is 3. The prime factorization of 27 is 3*3*3 The prime factorization of 39 is 3*13 So the GCF of 27 and 39 is 3.
31 x 131 = 39
37 is prime. 3 x 13 = 39 The GCF is 1.
The GCF of 12, 24, and 39 is 3.The prime factorization of 12 is 2*2*3The prime factorization of 24 is 2*2*2*3The prime factorization of 39 is 3*13So the GCF of 12, 24, and 39 is 3.
The prime factorization of 39 is 3 X 13.
156 = 4 * 39 = 22 * 39
The prime factorization of 39 is: 13 * 3 *1
39 3,13
39=3x133 x 13 = 39
The GCF of 14, 31, 39, and 56 is 1. One way to solve the problem is to notice that 31 is prime, and can't possibly be a factor of 14, which is smaller.If you prefer, you can write the prime factorization of each number in the set and find the GCF:The prime factorization of 14 is 2*7The prime factorization of 31 is 31 (1*31)The prime factorization of 39 is 3*39The prime factorization of 56 is 2*2*2*7So the GCF is 1.
No, 39 isn't prime.