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What is the prime factorization using exponents 130?

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Anonymous

∙ 10y ago
Updated: 8/21/2019

2 x 5 x 13

No exponents required.

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Wiki User

∙ 10y ago
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Related Questions

Prime factorization of 130 using exponents?

It is: 2*5*13 = 130 and exponents are not needed


What is the prime factorization using exponents of 130?

Prime factorization of 130 is 2x5x13, (or 21x51x131 if unnecessary exponents must be shown).


What is the prime factorization of 130 using a factor tree?

2*5*13 = 130


What is the prime factorrization of 130?

The prime factorization of 130 is 2x5x13.


What is a prime factorization for 130?

The prime factorization is: 2 x 5 x 13


What is a prime factorizaton for the number 130?

The prime factorization of 130 is 2 x 5 x 13.


How many times does the prime factor 2 appear in the factorization of 130?

You can find the prime factorization of 130: 130 = 2*5*13 Therefore the answer is 1. Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.


What is the Prime Factorization of 130?

Prime factorization of 130 is: 2 x 5 x 13. 2 x 5 x 13 = 130 2 x 5 x 132 x 5 x 13 = 130


What is tbe prime factorization of 130?

2 x 5 x 13 = 130


What is the prime factoriztion of 130 using exponents?

2 x 5 x 13 = 130. You can write that as 21 x 51 x 131 = 1301 but it's not necessary.


Prime factorization for 130?

2 x 5 x 13


What is prime factorization of 130?

2 x 5 x 13

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