Q: What is the prime fatorization of 243 using exponents?

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35 = 243

35 = 243

The prime factorization of 243 will require 5 numbers. It is possible to write a factorization in two numbers, but they won't both be prime. 3 x 3 x 3 x 3 x 3 = 243 9 x 27 = 243

243 = 3 x 3 x 3 x 3 x 3 = 35

No because they are both composite numbers

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35 = 243

35 = 243

35 = 243

35 = 243

none.

IS 243 PRIME OR COMPOSITE

The prime factors of 243 are 3 * 3 * 3 * 3 * 3 So 243 = 3^5

243 is a composite number.

It is only 3 that is a prime factor of 243

243 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 243 are 1,2,3,4,9,27,81, and 243.The factor pairs of 243 are 1 x 243, 3 x 81, and 9 x 27.The proper factors of 243 are 1, 3, 9, 27, and 81 or,if the definition you are using excludes 1, they are 3, 9, 27, and 81.The prime factors of 243 are 3, 3, 3, 3, and 3. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factor (listing each prime factor only once) of 243 is 3.The prime factorization of 243 is 3 x 3 x 3 x 3 x 3 or, in exponential form, is 35.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.

No, it's not. 243 is divisible by 3 and 81. To be prime, a number's only factors must be 1 and itself.

35 is 243 (81 * 3 = 243), and 3-2 = 1/9, thus:35 x 3-2=243 x 1/9 = 27Or, using the law of exponents:35 x 3-2 = 33 = 27