The probability of tossing two coins one time and not getting two heads is 3/4 or 75%. The possible out comes of this are: HH, HT, TH, TT. There is only one way to get two heads, out of four possible results. Another, faster way to do this problem would be to multiply the probability of getting one head on one coin (1/2) by the probability of getting a head on another coin (also 1/2). This will result in 1/4. Because you want every result BUT this one, subract this answer from one. You will get the an answer of 3/4. This may not seem like a faster method when writing it out, but with a larger number of coins it would save a lot of time, because you do not have to go through all of the combinations.
If they are fair coins, it is 1/16.
It is 3/4 or 0.75
The probability of tossing heads on all of the first six tosses of a fair coin is 0.56, or 0.015625. The probability of tossing heads on at least one of the first six tosses of a fair coin is 1 - 0.56, or 0.984375.
The probability of something NOT happening is the complement of the probability of something happening. Since the probability that you DO have 3 heads is 1/8 (that is, 1/2 cubed), the complement is 1 - 1/8 = 7/8.
50:50, or 50%
1/16
It is 0.3125
It is 3/8
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
It is 1/8 = 0.125
Assuming it is a fair coin, the probability is 1/24 = 1/16.
the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance