There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.
However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the required probability is 0.3126.
The probability of a boy is still 0.5 no matter how many prior children there are.
1/32
We would need to know the number of children in the family to answer this question. For instance, the probability of having no girls in a family of two children would be 1/4 theoretically. In general it is 2-n where n is the number of children.
The probability is 2 - 6
you have a 75% chance
The probability of a boy is still 0.5 no matter how many prior children there are.
50%
50/50
1/32
We would need to know the number of children in the family to answer this question. For instance, the probability of having no girls in a family of two children would be 1/4 theoretically. In general it is 2-n where n is the number of children.
Assuming boys are equally as likely as girls, 125 boys would be expected. The probability of getting 140 or fewer boys is approximately 97.51%
The probability is 2 - 6
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
you have a 75% chance
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
It depends on the couples' genes. Also, at present the probability of a girls is approx 0.48
The probably of four girls in a family with four children is 1/16. I got this answer because: Probability of a girl is 1/2 and to get all girls you would multiply it by 1/2 for the rest of the girls.