Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381
Oh, what a lovely thought! The probability of giving birth to a girl is 1/2 each time, so the probability of having 5 girls in a row is (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32. Remember, each birth is a unique and wonderful event, no matter the outcome.
To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.
The question is unclear. What do you mean by "almost heads". Please restate the question.
you have a 75% chance
It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.
Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.
The probability of having a boy or a girl is always 50/50 each time, regardless of previous outcomes. So the theoretical probability of having a girl after having three boys in a row is still 50%.
Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381
Each chance of a having a girl is 50% or 1/2. Three different children are separate events and so multiplying the chance all three together gives 1/2 x 1/2 x 1/2= 1/8. 1 in 8 chances will someone have three girls in a row.
Oh, what a lovely thought! The probability of giving birth to a girl is 1/2 each time, so the probability of having 5 girls in a row is (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32. Remember, each birth is a unique and wonderful event, no matter the outcome.
To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.
The question is unclear. What do you mean by "almost heads". Please restate the question.
Every time 2 people mate to produce an offspring, there is a 50/50 chance it will either be a boy or a girl. This can be explained using a Punnet Square. XX is a girl and XY is a boy. XX XY XX XY XX XY The chance of a mom having one girl is 50? or 1/2 The chance of her having a second girl is 1 in 4, or 25% The chance of her having 3 girls is 1 in 8, or 12.5% The chance of her having 4 girls in a row is 1 in 16, or 6.25% It is unlikely, but certainly possible.
(assuming that the probability of having a girl or a boy is 50/50) Looking from beforehand, the probability of having three boys then a girl is the probability of each of these events happening multiplied together. That is 50% x 50% x 50% x 50% or 0.54 This would mean that the chance of having a girl after three boys is 0.0625. If you've already had the three boys though, it is a different story. The point is that previous experiences do not affect future ones; probability has no memory. Thus the probability of having a girl next is 50%, regardless of if you've had boys or girls in the past. To think otherwise is known as the gambler's fallacy, where a gambler says "black has come up 4 times in a row, it must be red next" even though the chance of red is always 50%