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Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.

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Q: What is the probability of having 3 baby girls in a row?
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Continue Learning about Statistics

What is the probability of a couple giving birth to five girls in a row?

Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.


What is the probability of having three boys in a row?

This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381


Probability that an event will not occur?

To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.


What is the probability to giving birth to 5 girls in a row?

Oh, what a lovely thought! The probability of giving birth to a girl is 1/2 each time, so the probability of having 5 girls in a row is (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32. Remember, each birth is a unique and wonderful event, no matter the outcome.


When a coin is tossed 10 times in a row what is the probability of having almost heads?

The question is unclear. What do you mean by "almost heads". Please restate the question.