If I understand the question correctly, the answer is 3/10.
There are (99 - 9) = 90 2-digit numbers.13 of them are multiples of 7.The probability is 13/90 = 14.4% (rounded)
-3
1/2
The probability is 1/2.
The probability is 1/2.
No. A number with multiple digits does not have a place value. A single digit in a multi-digit number has a place value.
Add up the digits in a number, and if that sum is a multiple of 3, then the original number is also a multiple of 3. So 1 + 8 + 9 = 18, which if you're still not sure then 1+8=9, which is a multiple of 3. You can repetitively sum the digits until you have a result of a single digit number. If the single digit result is 3,6 or 9, then the original number is a multiple of 3. Also, if the single digit number is 9, then the number is also a multiple of 9. However, if the result is 6, then it is not necessarily a multiple of six.
No. To check if a number is a multiple of 3 add its digits together and if this sum is a multiple of 3, then so is the original number. This sum can be continued until a single digit remains; if the single digit is 3, 6 or 9 then the original number is a multiple of 3, otherwise not. 19 → 1 + 9 = 10 10 → 1 + 0 = 1 which is not 3, 6 or 9, so 19 is not a multiple of 3.
It is 0.45
It is 4/9
The only positive two-digit multiple of 12 and 10 is 60.
Divide the two-digit number by the one-digit number. If the remainder is zero then the 2-digit number is a multiple and if not, it is not.