Add up the digits in a number, and if that sum is a multiple of 3, then the original number is also a multiple of 3. So 1 + 8 + 9 = 18, which if you're still not sure then 1+8=9, which is a multiple of 3. You can repetitively sum the digits until you have a result of a single digit number. If the single digit result is 3,6 or 9, then the original number is a multiple of 3. Also, if the single digit number is 9, then the number is also a multiple of 9. However, if the result is 6, then it is not necessarily a multiple of six.
divisible of 4,2,1
If it's even and divisible by 3, it's divisible by 6.
The last three digits are divisible by 8.
If it ends with an even number then it is divisible by 2
To determine if a number is even or odd, you can check if the number is divisible by 2. If the number is divisible by 2 without leaving a remainder, then it is even. If the number is not divisible by 2 or leaves a remainder when divided by 2, then it is odd.
There is not an easy way without some division. The simplest is to check the divisibility of the number formed by the last three digits.
divisible of 4,2,1
If you can cut it in half three times and get a whole number each time, it's divisible by 8.
Without doing a safety inspection we can not tell you.
If it's even and divisible by 3, it's divisible by 6.
If it ends in a zero, which it does, it is divisible by 5.
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If it ends with an even number then it is divisible by 2
The last three digits are divisible by 8.
I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138
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1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.