Let's call the chance of drawing a 9 on the first draw P(A). Since there are four 9s, P(A) is 4/52. Probability of not drawing a 9 is 1-(4/52). Each draw is independent so we multiply the probabilities. The probability of EXACTLY one 9 in two draws if P(A)P(1-A)=12/169 which is a about .071
The probability of drawing aces on the first three draws is approx 0.0001810
O.25
If you draw 40 cards without replacement the probability is 1! If you draw just one, the probability is 1/4.
The probability, if you draw 40 cards, without replacement, is 1. That is, it is a certainty. The probability on a single random draw is 1/4.
The answer depends on how many cards are drawn, and whether they are drawn with or without replacement. If 1 card is drawn, the probability is 0, if 50 cards are drawn (without replacement), the probability is 1. If only two cards are drawn, at random and without replacement, the probability is (4/52)*(3/51) = 12/2652 = 0.0045
The probability of drawing a queen or king, in a single randomly drawn card, is 2/13. The probability of drawing one when you draw 45 cards without replacement is 1. The probability of choosing has nothing t do with the probability of drawing the card. I can choose a king but fail to find one!
The answer depends on how many cards are drawn. If 40 are drawn without replacement, from a normal deck, the probability is 1. If 3 are drawn the probability is 0!
1 in 12 * 11 / 2 / 1 or 1 in 66.
The probability, if you draw 40 cards, without replacement, is 1. That is, it is a certainty. The probability on a single random draw is 1/4.
24 out of 6497400 = 1 out of 270725.
The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement. Without that information it is not possible to give a meaningful answer.
completely useless.