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It is (1/2)*(5/6) = 5/12

Q: What is the probability of getting a even number then not a 2 if you roll a number cube twice?

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The probability of getting an even number on both dice is (2/6) * (2/6) = (4/36) = 1/9. The probability when rolling two dice of getting one even number but not a "2" is 10/36, which is 5/18.

one fourth

It is 1/36.

It is 0.722... recurring.

If the cube is honest, then every number 1 - 6 has the same probability ... 1/6 = 16 2/3 %

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The probability of getting an even number on both dice is (2/6) * (2/6) = (4/36) = 1/9. The probability when rolling two dice of getting one even number but not a "2" is 10/36, which is 5/18.

Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.

one fourth

50 percent

It is 1/36.

It is 1/2.

It is 0.722... recurring.

If the cube is honest, then every number 1 - 6 has the same probability ... 1/6 = 16 2/3 %

1/4

It is 2/3.

it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...

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