Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in Tails exactly twice?
The three possible (winning) outcomes are:
TTH
THT
HTT
The other (losing) outcomes are:
HHH
HHT
HTH
THH
TTT
So there is a 3 in 8 chance or a probability of 3/8 = 0.375
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
ye
It is 1/2.
The probability is 1/4
Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %
The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.
you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .
2 to 1
ye
It is 0.2503, approx.
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375