There are 4 aces in a deck, a deck consists of 52 cards
4/52*3/51 ≈ 0.45% that 2 cards with the same value would end up next to each other
The probability of drawing one black seven from a standard deck of cards is 2/52 = 1/26. The probability of drawing the other black seven from the remaining 51 cards is 1/51. Therefore the probability of drawing both black sevens from a deck of cards = 1/26 x 1/51 = 1/1326 ~ 0.000754 (3sf).
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
I just programmed a small software and find a 75,6% of two cards beein next to each other in 15 million random generated decks.
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4
The probability of having a girl versus a boy is 1/2 because there is two things you have a chance of getting and you can only get one or the other.
The probability of drawing a heart from a fair deck is 1 in 4. If the card is replaced then the probability is again 1 in 4. The probability of drawing a card other than a heart is 3 in 4. Once again if the card is replaced then the probability remains 3 in 4
The probability of not getting a club is the same as the probability of getting one of the other suits. There are (52-13)=39 such possibilities out of 52. Hence the probability is 39/52=3/4.
The probability of drawing one black seven from a standard deck of cards is 2/52 = 1/26. The probability of drawing the other black seven from the remaining 51 cards is 1/51. Therefore the probability of drawing both black sevens from a deck of cards = 1/26 x 1/51 = 1/1326 ~ 0.000754 (3sf).
4/52 * 4/51 or about .006 This is assuming no other cards were drawn beforehand.
The probability of choosing a red or black card from a standard deck of 52 cards is 52 in 52, or 1 in 1. In other words, it will happen no matter what.
I just programmed a small software and find a 75,6% of two cards beein next to each other in 15 million random generated decks.
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
If 2 cards are selected from a standard deck of 52 cards without replacement, in order to find the probability that both are the same suit, start with the first card...The probability that the first card is any suit is 52 in 52, or 1.Now, consider the second card. There are 12 cards remaining in the same suit, and 39 cards remaining in the other three suits...The probability that the second card is the same suit as the first card is 12 in 51, or 4 in 17, or 0.235.The probability of both events occurring is the product of those two probabilities. That is still 4 in 17, or 0.235.
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