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What is the probability of picking 20 red marbles out of a bag with 50 marbles where only 20 of them are red and the rest are blue?
Wiki User
∙ 14y ago
it's 20/50 times 19/49 times 18/48 tmes 17/47 etc down to 1/31
Wiki User
∙ 14y ago
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What is the probablility of picking a green marble at random from a box that contains only 11 blue marbles?
The probability of picking a green marble from a box that only contains blue marbles is zero.
If you had ten marbles 3 blue and 7 red and you picked out three marbles at the same time what would be the odds of picking 2 blue marbles?
1 in 5.45 of picking at least 2 blue marbles any 2 from 3 is 3 correct picks =3X7(red)=21 of 2 blue only 1 pick of 3 blue only any 3 from 10=120 120/22=5.45
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
What does equally likely events in math term mean?
When you are asked what is the probability of drawing "thing a" when you have only the same amount of "thing b," is called an equally likely event. For example: In a hat you have 8 black marbles and 8 black marbles. Since there the same amount of both, the chance of picking a black marble is 50% and picking a blue marble is 50%. This is an equally likely event.
If a bag contains three red and three blue marbles and if three marbles are chosen without replacement what is the probability that they will be all red or all blue?
There are 6!/3! = 120 possible combinations of marble colour. Of these, only 2 are "good". This gives a probability of 2/120 = 1/60 = 0.0167, or about one and two-thirds of a percent.
What is the probablility of picking a green marble at random from a box that contains only 11 blue marbles?
The probability of picking a green marble from a box that only contains blue marbles is zero.
A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles If Joe picks 1 marble from the bag at random what is the probability that it will be blue?
1 in 15 chances that the marble will be blue, because there are 15 marbles all together in a bag, and you are only picking one out of it.
If you had ten marbles 3 blue and 7 red and you picked out three marbles at the same time what would be the odds of picking 2 blue marbles?
1 in 5.45 of picking at least 2 blue marbles any 2 from 3 is 3 correct picks =3X7(red)=21 of 2 blue only 1 pick of 3 blue only any 3 from 10=120 120/22=5.45
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
If a bag contains 3 green marbles 5 blue marbles and 2 yellow marbles find the probability that the marble is blue?
Assuming that you're only taking out one marble, then:Your sample space --> 3 + 5 + 2 = 10The probability of getting a blue marble on the first draw is 3/10 or 0.3
What is a probalitlity for math?
A probability is saying something like, "What is the probability of getting a red marble if there are 20 red marbles in a bag and fifty blue marbles?" The answer would be 20/70 or 2/7 because there are seventy marbles in the bag but you only want those twenty.
What does equally likely events in math term mean?
When you are asked what is the probability of drawing "thing a" when you have only the same amount of "thing b," is called an equally likely event. For example: In a hat you have 8 black marbles and 8 black marbles. Since there the same amount of both, the chance of picking a black marble is 50% and picking a blue marble is 50%. This is an equally likely event.
A bag contains only blue and gray marbles if there are 18 blue marbles and 20 gray marbles in the bag what is the ratio to blue marbles and gray marbles?
9:10
If a bag contains three red and three blue marbles and if three marbles are chosen without replacement what is the probability that they will be all red or all blue?
There are 6!/3! = 120 possible combinations of marble colour. Of these, only 2 are "good". This gives a probability of 2/120 = 1/60 = 0.0167, or about one and two-thirds of a percent.
What is the probability of picking 3 from 20 in fraction form?
The probability of picking a distinct set of 3 numbers from 20 is1/[20!/(3!)(17!)]= 1/1140The probability of only picking 3 from 20 is1/20
Bill has a bag of marbles If he knows that his bag contains 2 blue 3 red and 4 clear marbles what are the odds for Bill choosing a clear marble or a blue marble if he pulls one marble from the bag?
2/3rd is the answer This is a case of probability, the probability of getting only blue marble is 2/9 and only clear marble is 4/9, since we are looking for either of blue or clear, we will add the probabilities and upon adding these two it is 6/9 which translates into 2/3rd.
A bag contains 3 blue marbles and 4 red marbles. What is the probability that three randomly drawn marbles without replacement will all be red?
The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
