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11 marbles total and 6 are blue so probability is 6/11

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6y ago
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6y ago

6/11 or 54.5%

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Q: What is the probability of picking a blue marble from a bag of 4 red marbles 6 blue marbles and 1 white marble?
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Related questions

What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?

The probability of drawing a white marble is .46


A bag contains 4red marbles 2 white marbles a marble is selected kept out the bag and then another marble is selected what is the probability of selecting a red marble and then white marble?

2/6


If a box contains 4 red marbles seven white and 5 blue and two marbles are drawn one at a time with replacement What is the probability that both marbles are white?

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.


What is the probability of drawing a marble that is not white?

It depends on how many marbles of each colour you have....


A bag contains 6 purple marbles and 7 white marbles Two marbles are drawn at random One marble is drawn and not replaced Then a second marble is drawn What is the probability that the first marble?

There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.


If you have three marbles red white and blue what is the probability that you do not get a white or blue marble?

1 in 3


When a jar contains 5 white marbles 3 blue marbles and 2 green marbles and if one marble is drawn at random then what is the probability that it will be blue?

There is a probability of 3 that it will be blue.


If there are 3 black marbles 2 white marbles and 1 red marble what is the probability of selecting a black marble?

3/6 or 1/2 or 50%


What is the equation used to determine probability?

Number of possibilities for one category / Total of all possibilities. For example, if I had a bag of marbles where there are three white marbles and two black marbles. The probability of pulling out a white marble is how many white marbles are in the bag which is: three. But the total of things you can draw out of the bag can either be one of the three white marbles or one of the two black marbles. 3 white marbles+ 2 Black marbles= five marbles. Possibility is 3/5 for drawing a white marble.


A bag contains 6 purple and 7 white marbles two marbles are drawn at random one marble is drawn and not replaced what is the probability that the fist marble is white and the second is purple?

2/13


How do you Write a combination problem and solve it?

A combination problem essentially asks for two answers from different mathematical areas. A simple example could be, "A boy has a bag of marbles. Four marbles are blue. Three marbles are red. Five marbles are white. How many marbles does he have all together? What are the chances of picking a blue marble at random?" The two areas being addressed are simple addition and probability. There are a total of 12 marbles. There is a 1:3 chance of picking a blue marble at random.


What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?

5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.