Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
The probability of drawing a white marble is .46
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.
15/27. Simply take the probability of drawing a blue marble.
Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
The probability of drawing a white marble is .46
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
4 out of 7
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
The odds of pulling a red marble on the first try is 4/15 or about .27 and the probability of drawing a white marble the second time if a the first is a red marble is 5/14 or about .36. the odds of both happening is the product of the probabilities of the other events, or 2/21.
15/27. Simply take the probability of drawing a blue marble.
2/6
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.