The answer depends on what you are rolling. With an ordinary die, the answer is 1 (a certainty)..
If you keep rolling the die, then the probability of rolling a 6 and then a 1 on consecutive rolls is 1.The probability is 1/36 for the first two throws.
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
It is 1/36.
The probability of rolling a specific number on a fair six-sided dice is 1/6, as there are 6 equally likely outcomes. When rolling the dice 300 times, the probability of rolling that specific number on each roll remains 1/6, assuming the dice is fair and each roll is independent. Therefore, the probability of rolling that specific number at least once in 300 rolls can be calculated using the complement rule, which is 1 minus the probability of not rolling the specific number in all 300 rolls.
If the die is rolled often enough, the probability is 1. With only two rolls of a fair die, the probability is 1/6.
I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
In two successive rolls, it is 1/6 otherwise it is a near certainty.
To determine the experimental probability of rolling a 4, you need to divide the number of times a 4 was rolled by the total number of rolls conducted in the trial. For example, if a 4 was rolled 3 times out of 20 rolls, the experimental probability would be 3/20, or 0.15. This probability reflects the observed outcomes based on the specific trial conducted.
1/6,3/6 ----------------------------------------------------------------------------------------------------- The probability of rolling a 2 is: P(2) = 1/6 The probability of rolling an even number is: P(even) = 1/2 The result on the second roll is independent of the result in the first roll. The probability of rolling a 2 and then rolling an even number is: P(2,even no.) = (1/6) ∙ (1/2) = 1/12 = 0.08333... ≈ 8.33%
The probability is 0.1241