The probability of rolling a specific number on a fair six-sided dice is 1/6, as there are 6 equally likely outcomes. When rolling the dice 300 times, the probability of rolling that specific number on each roll remains 1/6, assuming the dice is fair and each roll is independent. Therefore, the probability of rolling that specific number at least once in 300 rolls can be calculated using the complement rule, which is 1 minus the probability of not rolling the specific number in all 300 rolls.
Chat with our AI personalities
Well, honey, the probability of rolling a specific number on a fair six-sided dice is 1/6. So, if you roll the dice 300 times, the probability of getting that specific number is 300/6, which simplifies to 50. So, you've got a 50% chance of rolling that number at least once in 300 rolls.
The probability is the number of times that a specific outcome occurred divided by the number of repetitions of the relevant trial.
If George rolls the die 300 times, how many fives will he roll?
120 times.
300 times. In the ones place it occurs ten times per each 100 [5,15,25,...95] so 10x10 =100. Then in the tens place it also occurs ten times each 100 [50,51,52,53...59] We already counted 55 as one for the ones place and now we're counting 1 for the tens place. In the hundreds place, from 500 to 599 there are 100 fives (we already counted the tens and ones places. So 100 + 100 + 100 = 300.
The digit 9 appears in the units place 100 times from 1 to 1000 (9, 19, 29,..., 989, 999). It also appears in the tens place 100 times (90, 91, 92,..., 99, 190, 191,..., 199, 290,..., 999). Therefore, the digit 9 appears a total of 200 times from 1 to 1000.
300 points scored in bowling?