With two six-sided dice, there are 36 possible outcomes. Let's look at the outcomes which the sum is less than or equal to 4: {1.1 1.2 1.3 2.1 2.2 3.1} That's 6 outcomes, which leaves 30 outcomes with greater than 4. So 30/36 = 5/6 or 83.333%
The probability of rolling more than a six with one roll of a cube whose sides are marked from 1 to 6 is zero.
The probability of rolling a number greater than 4 is 2/6, that is, 1/3. For the probability of pulling out a red marble, more data has to be known. Just put the number of red marbles in the numerator, the total number of marbles in the denominator. Finally, multiply the two probabilities.
There are 36 permutations of two dice. Only one of them has a sum of two. Then probability, then, of rolling a sum of more than two is 35 in 36, or about 0.9722.
Total number of possible outcomes = 6.Number of them that are more than 2 = 4. (3, 4, 5, and 6)Probability of rolling more than 2 = 4/6 = 2/3 = 662/3%
It depends on "rolling a sum of 1" with what. One die, two dice or more?
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.
The probability is 1/6.
The experiment is not defined! The probability of the event described, when 9 or more number cubes are rolled, is 0.
The probability of rolling more than a six with one roll of a cube whose sides are marked from 1 to 6 is zero.
The probability of rolling a number greater than 4 is 2/6, that is, 1/3. For the probability of pulling out a red marble, more data has to be known. Just put the number of red marbles in the numerator, the total number of marbles in the denominator. Finally, multiply the two probabilities.
The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice
The answer depends on what you are rolling: three or more ordinary dice, or fewer dice with non-standard numbers on them, or a die with some other shape.
There are 36 permutations of two dice. Only one of them has a sum of two. Then probability, then, of rolling a sum of more than two is 35 in 36, or about 0.9722.
Total number of possible outcomes = 6.Number of them that are more than 2 = 4. (3, 4, 5, and 6)Probability of rolling more than 2 = 4/6 = 2/3 = 662/3%
It depends on "rolling a sum of 1" with what. One die, two dice or more?
Depends on what you are rolling - a cubic die or a more exotic shape.
When rolling a die, a 1, or a 2, or a 3, or a 4, or a 5, or a 6 will come up. Factors of six are 1, 2, 3 and 6. This leaves 4 and 5 that are not factors of 6. The probability of rolling any one number in one roll of the die is 1 in 6, or 1/6. To find a "cumulative" probability where we "combine" the odds of rolling several numbers, as is the case here, we simply add the probability of rolling each number together and sum them.In the case here, the probability of rolling 1 is 1/6, and the probability of rolling 2 is also 1/6, and the probability of rolling 3 is 1/6 and the probability of rolloing 6 is 1/6. We add 1/6 + 1/6 + 1/6 + 1/6 and get 1+1+1+1/6, which is 4/6. The 4/6 reduces to 2/3, and that 2/3 represents the probability of rolling a factor of 6 with one roll of a die. There is one more little thing.Probability is a mathematical term where "odds" are expressed on a scale of zero (0) to one (1). The probability of something happening is either 0, or 1, or something in between. If the probability of something happening is 100% (which is to say that somehting must occur), then the probability is 1. And if something cannot happen, then the probability of it occurring is 0. In this light, the 2/3 chance of rolling a factor of 6 with one roll of a die is 0.6666....