The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.
For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".
Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice
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The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
90.47619% Close but no cigar. I presume u r talking about rolling a pair of dice. There are 6 possible outcomes 4 each die, all equally likely, for a total of 36 equally likely possible outcomes. There is only 1 with a sum of 2, and 2 with a sum of 3, for a total of 3 outcomes with a sum of 3 or less. That's 3 out of 36, or 1/12. The other 11/12 represent a sum of more than 3, and that's 91.6666666...%
Assuming you mean the sum of the two dice is a prime number, then: The possible outcomes are 2, 3, 5, 7, 11 which occur 1, 2, 4, 7, 2 times respectively. There are 36 possible outcomes → pr(prime_sum) = (1+2+4+7+2)/36 = 16/36 = 4/9 If you mean that both dice must show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a prime number is 3/6 = ½ → probability both show a prime number is ½ × ½ = ¼ If you mean either or both dice could show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a primes is 3/6 = ½ → probability of a die not showing a prime is 1 - ½ = ½ → probability of neither die showing a prime is ½ × ½ = ¼ → probability of either or both dice show a prime is 1 - ¼ = ¾
Total different rolls are 36 (6x6) Ways to roll an 11 is 2 (5/6 and 6/5) Probability = number_of_rolls_of_success/total_number_of_rolls = 2/36 = 1/18
11 outcomes if the dice are indistinguishable, 36 otherwise.