7/12 ≈ 0.583
Probability is number_of_ways_of_success/total_number_of_ways.
There are 36 possible ways 2 dice can land when thrown.
To be more than 6, the sum can be 7, 8, ..., 12
There is 1 way to achieve 12 (6 & 6);
2 ways to achieve 11 (5 & 6 and 6 & 5);
...
6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1);
A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6.
Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.
The probability for dice depends on how many. For a die, it is 1/3.
2 over 6
Prob(Rolling a number greater than 2) = 1 - Prob(Not rolling a number greater than 2 on either die) = 1 - Prob(Rolling a number less than or equal to 2 on both dice) = 1 - Prob(Rolling a number less than or equal to 2 on a die)2 = 1 - (1/3)2 = 8/9
the probabilty is 4 out of 6 our 2/3
1/2, 0.5, 50%, or half a chance.
The probability is 1.
The probability for dice depends on how many. For a die, it is 1/3.
2 over 6
The probability is 26/36 or 13/18
Prob(Rolling a number greater than 2) = 1 - Prob(Not rolling a number greater than 2 on either die) = 1 - Prob(Rolling a number less than or equal to 2 on both dice) = 1 - Prob(Rolling a number less than or equal to 2 on a die)2 = 1 - (1/3)2 = 8/9
It is 1/12.
the probabilty is 4 out of 6 our 2/3
The answer depends on what you are rolling: three or more ordinary dice, or fewer dice with non-standard numbers on them, or a die with some other shape.
1/2, 0.5, 50%, or half a chance.
5/36
It is 0.8181... recurring.
In the case of dice, greater than three, means 4,5 or 6. So, obviously, three cases out of 36.