What is the probability of tossing two number cubes with faces numbered 1 though 6 and getting a number greater than 2 on one cube and a number less than 2 on the other?

Answer 1

If you were throwing one numbered cube (dice) with each face numbered 1 to 6, then the chance of getting a number greater than two is 4/6 (or 2/3) since there are 4 numbers greater than 2, and six numbers in total.

Similarly, if you were throwing one dice, the chance of getting a number less than 2 is 1/6.

To determine the probability of getting both of these outcomes on two dice (greater than 2 on one dice and less than 2 on the other) we simply multiply these two values together.

2/3 x 1/6 = 2/18 = 1/9.

So there is a one in nine chance of this outcome occuring.