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Q: What is the probability of tossing an eight sided dice with numbers one through eight and getting an even number greater than or equal to four?

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The probability is 17C4 = 2380

If the only numbers to pick from are 1 through 8, how can you get a factor greater than 10?

There are 20 numbers from 20 through 39, and 4 of them are prime (23, 29, 31, 37), the probability is 4 in 20 or 0.20.

It is 0.4

The simplest way to get a probability of zero is to have an impossible event. For example, with a die (that's the singular of "dice") that has the numbers 1-6, getting each of these numbers has a probability of 1/6; getting the number has a probability of 0.There is another way to get a probability of zero, which occurs for certain situations that involve infinity; if you are prepared to read through some somewhat intense math, check the Wikipedia article on "Almost surely" for more details. (In this case, "almost surely" means a probability of 1; while "almost never" means a probability of 0.)

The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.

A spinner has the numbers 1 thru 9. What is the probability of P(less than 6)? Write the answer as a decimal.

There are 4 numbers (7-10) which are greater than 6 → pr(>6) = 4/10 = 2/5

The probability is 1/42.

There are 15 primes from 1 to 49 (including '1').The probability is (15/49) = 30.612 %(rounded)

A 6-sided die has 6 possible outcomes. If each of the sides has a different number, one through six, then the probability of getting any one number is 1/6.

1/6 or (16 and 2/3)%

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