The probability is 0.664
It is the Standard Normal distribution.
4 in 52, which equals 1 in 13.
a and b both have the probability of 3/4
For a binomial probability distribution, the variance is n*p*q which is 80*.3*.7 = 16.8. The standard deviation is square root of the variance which is 4.099; rounded is 4.1. The mean for a binomial probability distribution is n*p or 80*.3 or 24.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
It is the Standard Normal distribution.
4 in 52, which equals 1 in 13.
0.8413
There are 2 black queens and 26 red cards in a standard deck. Therefore the probability is 28/52 = 7/13 = 53.85%
a and b both have the probability of 3/4
For a binomial probability distribution, the variance is n*p*q which is 80*.3*.7 = 16.8. The standard deviation is square root of the variance which is 4.099; rounded is 4.1. The mean for a binomial probability distribution is n*p or 80*.3 or 24.
The probability that an event will occur plus the probability that it will not occur equals 1.
The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
It does not matter.
It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.
Probability equals favorable outcomes divided by total number of outcomes.