The probability is 0.664
It is the Standard Normal distribution.
4 in 52, which equals 1 in 13.
For a binomial probability distribution, the variance is n*p*q which is 80*.3*.7 = 16.8. The standard deviation is square root of the variance which is 4.099; rounded is 4.1. The mean for a binomial probability distribution is n*p or 80*.3 or 24.
a and b both have the probability of 3/4
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
It is the Standard Normal distribution.
4 in 52, which equals 1 in 13.
0.8413
There are 2 black queens and 26 red cards in a standard deck. Therefore the probability is 28/52 = 7/13 = 53.85%
a and b both have the probability of 3/4
For a binomial probability distribution, the variance is n*p*q which is 80*.3*.7 = 16.8. The standard deviation is square root of the variance which is 4.099; rounded is 4.1. The mean for a binomial probability distribution is n*p or 80*.3 or 24.
The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.
The probability that an event will occur plus the probability that it will not occur equals 1.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
It does not matter.
It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.
Probability equals favorable outcomes divided by total number of outcomes.